5x^2-17x-162=0

Solution for 5x^2-17x-162=0 equation:

5x^2-17x-162=0

a = 5; b = -17; c = -162;
Δ = b2-4ac
Δ = -172-4·5·(-162)
Δ = 3529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{3529}}{2*5}=\frac{17-\sqrt{3529}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{3529}}{2*5}=\frac{17+\sqrt{3529}}{10}
$